Direct Proportion Calculator
Find the constant of proportionality k from one known pair, then predict any other value on the line y = kx.
Open → Direct Proportion CalculatorFor quantities that move in opposite directions — more workers, fewer days. Enter one known pair to find the constant product, then solve for whichever value you are missing. The graph shows the hyperbola and the table shows the product staying fixed.
Formula x × y = k
Use this when one quantity going up means the other goes down — more workers means fewer days, faster speed means less time. If both move the same way, you want the direct proportion calculator instead.
The known pair
The new value
● the known pair · ● the value you asked for · the curve approaches both axes without ever reaching them
| x | y | x × y |
|---|
The third column never changes. A constant product is what makes this an inverse proportion — compare a direct proportion, where the constant is the ratio.
The mirror image of direct proportion: where that one divides to find the constant, this one multiplies.
Check the relationship really is inverse
Ask what happens if you double one quantity. If the other halves, it is inverse. If it also doubles, it is direct. If it changes by some other amount, it may be neither — a job that gets less efficient with more people on it is not a clean inverse proportion.
Multiply the known pair to get k
k = x₁ × y₁. Give the result its units and it usually names something
real: workers × days is person-days of work, speed × time is
distance, pressure × volume is proportional to the
energy in the gas.
Write x × y = k
With k = 48 the equation is xy = 48, or y = 48/x. Any pair
of numbers multiplying to 48 is a valid state of this system.
Divide k by the value you know
Unlike direct proportion, the operation is the same in both directions:
y = k/x and x = k/y. Whichever value you have, divide k by
it. This symmetry is a useful check that you have the right kind of relationship.
Confirm the direction of the answer
If you increased x, the answer for y must be smaller than y₁. If it came out larger, you multiplied where you should have divided.
Inverse proportion. The product is fixed. Because the equation is symmetric in x and y, finding either one from the other is the same division.
Pair form. Both pairs give the same product, so you can equate them directly and skip calculating k — handy for a one-off answer.
"6 workers take 8 days, so 48 workers take 1 day" is arithmetically right and practically wrong. Inverse proportion assumes the work divides perfectly and everyone works at the same rate. Real jobs have coordination costs and tasks that cannot be parallelised, so the model breaks down at the extremes.
6 workers finish a job in 8 days. How long for 12 workers?
4 days — twice the workers, half the time
A trip takes 4 hours at 60 mph. How long at 80 mph?
3 hours — and k is the distance
A gas at 300 kPa occupies 2 litres. What pressure at 5 litres, same temperature?
120 kPa
How many workers are needed to finish that same 48 person-day job in 3 days?
16 workers
Choosing the wrong one is the single biggest source of error in proportion problems.
Direct proportion
y = kx · the ratio y/x is fixed
Inverse proportion
xy = k · the product xy is fixed
| Situation | Which type | Why |
|---|---|---|
| Litres of petrol and total cost | Direct | More litres means more money — the price per litre is the constant. |
| Speed and time for a fixed distance | Inverse | Going faster cuts the time — speed × time is the fixed distance. |
| Number of servings and flour needed | Direct | Twice the servings needs twice the flour. |
| People sharing a fixed bill | Inverse | More people means a smaller share each — the total is the constant. |
| Gear teeth and rotation speed | Inverse | A bigger gear turns more slowly; teeth × rpm is fixed along the chain. |
| Hours worked and pay earned | Direct | The hourly rate is the constant of proportionality. |
| Taps filling a tank and time taken | Inverse | More taps means less time; tank volume is the constant. |
| Distance from a lamp and brightness | Inverse square | Brightness falls as 1/d², not 1/d — twice as far is a quarter as bright. |
In inverse proportion the constant k tends to be more meaningful than in the direct case, because it names a fixed total that is being divided up differently. Six workers over eight days is 48 person-days of labour; that 48 is the size of the job, and it does not change however you staff it. Sixty miles an hour for four hours is 240 miles; that 240 is the length of the route. Recognising what k is often answers the question faster than the algebra does.
This also gives you a quick way to check whether a problem is genuinely inverse. Multiply the two quantities and ask whether the product is a thing. Workers × days = work: yes. Kilograms × price = nothing in particular: so cost and weight are not inversely proportional, they are directly proportional. The test takes a few seconds and catches the most common misclassification.
On a hyperbola the same absolute change in x has wildly different effects depending on where you are. Going from 1 worker to 2 halves the time — an enormous saving. Going from 20 workers to 21 barely moves it. That flattening is why real projects hit a point where adding people stops helping, and it is visible in the shape of the graph long before you reach the practical limits.
Many real relationships are direct in one variable and inverse in another at the same
time. The time to finish a job is inversely proportional to the number of workers but
directly proportional to the size of the job: t = kS/w. These are handled by
finding the single constant that satisfies a fully specified case, then substituting the
new values for every variable at once. The principle is the same; there are simply more
quantities to keep track of.
For relationships where both quantities move together, use the
direct proportion calculator. If you have two
complete pairs and only want to know whether they are consistent, the
cross multiplication calculator tests it
in one step — remembering that for an inverse relationship you compare
x₁y₁ with x₂y₂ rather than cross-multiplying. And to turn a
constant into a per-unit figure, the
unit ratio calculator does that conversion.
Starting with the distinction from direct proportion, which is where most errors originate.
x × y = k, or equivalently y = k / x. The classic case is workers and time: if it takes 6 people 8 days, then 12 people take 4 days, because 6 × 8 = 12 × 4 = 48 person-days of work.k = x₁ × y₁. For 6 workers taking 8 days, k = 48. That constant usually has a concrete meaning — here it is the total amount of work measured in person-days, which is why it does not change when you redistribute the same job among more or fewer people.y = k / x², so doubling x divides y by four rather than two. Gravity, sound intensity and light brightness all fall off this way with distance. This calculator handles the simple inverse case y = k / x; for the squared version you would find k as y × x² instead.y = k / x has no value at x = 0 — division by zero is undefined — and y can never actually reach 0 either, since k / x only shrinks towards zero as x grows without ever arriving. The two axes are asymptotes: lines the curve approaches indefinitely closely but never meets.